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Pressure: Fundamental Principles and Applications in Fluids and Gases

Defining Pressure

Pressure (P) quantifies force distribution over a surface area:

    \[ P = \frac{F_{\perp}}{A} \]

Where:

  • F_{\perp}: Normal force component (N)
  • A: Contact area (m²)
  • 1 Pa = 1 N/m²

Fluid Pressure

Hydrostatic Pressure

    \[ P = P_0 + \rho gh \]

Where:

  • P_0: Atmospheric pressure (101.3 kPa)
  • \rho: Fluid density (kg/m³)
  • g: Gravitational acceleration (9.81 m/s²)
  • h: Depth (m)

Pascal’s Principle

Pressure transmission enables hydraulic force multiplication:

    \[ \frac{F_1}{A_1} = \frac{F_2}{A_2} \]

Gas Pressure

Ideal Gas Law

    \[ PV = nRT \]

Constants:

  • R = 8.314 \, \text{J/(mol·K)}
  • STP: 273.15 K, 101.325 kPa

Practical Applications

Engineering Systems

  • Hydraulic lifts: Achieve 100:1 force amplification
  • Scuba diving: Pressure increases ~101 kPa per 10m depth

Meteorology

  • Barometric pressure: 98-104 kPa typical range
  • Weather fronts: ~5 kPa pressure differences

Worked Example

Water Pressure at 5m Depth:

    \[ P = 1000 \, \text{kg/m}^3 \times 9.81 \, \text{m/s}^2 \times 5 \, \text{m} = 49.05 \, \text{kPa} \]

Note: Total pressure = 49.05 kPa + 101.3 kPa = 150.35 kPa

Common Errors

  1. Using gauge pressure instead of absolute pressure
  2. Neglecting temperature in gas law calculations
  3. Confusing density units (kg/m³ vs g/cm³)

Practice Problems

  1. A hydraulic press has pistons with 10:1 area ratio. What input force lifts a 500 kg mass?
  2. Calculate the moles of oxygen in a 0.02 m³ tank at 300 kPa and 293 K.
  3. Explain why submarines have maximum operating depths.

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